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(MAC-1105C) - Final Exam (Proctored)
College Algebra (4
Credit Hours)
I have the steps to solve the problems which should help you with any College Algebra Final Exam.
x = dimes x + 3 = quarters 0.10x + 0.25(x + 3) = 3.20 0.10x + 0.25x + 0.75 = 3.20 0.35x + 0.75 = 3.20 0.25x = 2.45 x = 7 = dimes x + 3 = quarters 7 + 3 = quarters The answer is 10. Let’s check the answer. Remember we have 7 dimes and 10 quarters (3 more quarters than dimes). .10(7) + .25(10) = 3.20 .70 + 2.50 = 3.20 3.20 = 3.20
As we look at the answer, we can see that we need to solve a quadratic equation, and not solve for x. So, we will put the equation into quadratic form. Add 32 to both sides of the equation. (3x+5)2 + 32 = 0 Simplify (3x + 5)2 + 32 Rewrite (3x + 5)2 as (3x + 5) (3x + 5) We are left with (3x+5) (3x+5) + 32 = 0 Expand (3x+5) (3x+5) using the FOIL Method 3x(3x) + 3x ⋅ 5 + 5(3x) + 5 ⋅ 5 + 32 = 0 Simplify and combine like terms. 9x2 + 30x + 25 + 32 = 0 Add 25 and 32 9x2 + 30x + 57 = 0 Now, solve the Quadratic Equation like we did earlier. 9x2 + 30x + 57 = 0 ![]()
Explanation The easiest way to graph this equation is to pick zero as the starting point.Then we use -3 in the y-intercept form as we are given -3 in the equation, so the first pair we plot would be (0,-3). Solution 2(0) – 3 = -3 Then we can use 1 as the second starting point and evaluate 1 in the equation to find the ordered pair. So, we know the equation is we use 2x – 3 to find the second ordered pair. Solution 2(1) – 3 = -1 Now we can graph the equation. (0,-3) > 2(0) – 3 = -3 (1,-1) > 2(1) – 3 = -1
t = time We would write this equation as so: 48t = 54(t – 2) Simplify 48t = 54t – 108 Subtract 54t from both sides. -6t = -108 Divide both sides by -6. t = 18 Let’s check the answer (please note Car B drove 2 hours less) 48t = 54 x (t – 2) 48(18) = 54 x (18 – 2) 48(18) = 54(16) 864 = 864 College Algebra (MAC-2233) Lessons: Pre-Assessment Exam Final Exam (Proctored) Page 1 2 3 More Lessons 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
|x| + 2 = 10 Subtract 2 from both sides. |x| = 8 Remove the absolute value term from the equation, so this means the answers can be: 8 or -8 Since the multiple-choice answer is -8, the answer is -8.
Explanation |x| + 2 = 10Subtract 2 from both sides. |x| = 8 Remove the absolute value term from the equation, so this means the answers can be: 8 or -8 Since the multiple-choice answer is -8, the answer is -8.
Add 13 to both sides. 11x = 44 Divide both sides by 11 x = 4
5x = 2.5 Divide both sides by 5. x = 0.5
The leading coefficient is the leading term, and the degree is 3 because it is the greatest exponent.
-6x = 24 Divide both sides by -6 x = -4 College Algebra (MAC-2233) Lessons: Pre-Assessment Exam Final Exam (Proctored) Page 1 2 3 More Lessons 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
We simply flip the second fraction, multiply, and simplify! So, 72 / 12 = 6
Explanation 2/10 + 4/10 = 6/10 Simplify by dividing by 2 = 3/55/6 – 1/6 = 4/6 = Simplify by dividing by 2 = 2/3 2/9 + 4/9 = 6/9 = Simplify by dividing by 3 = 2/3 8/12 – 2/12 = 6/12 = Simplify by dividing by 6 = 1/2
To write To write Now we combine all the terms We are left with Now we need another denominator so we what do is We multiple both sides by Now we need to multiply We are left with Now we have common denominators, so we can combine the top (the bottom keeps 12y as the denominator)
x + 0.2 = 0.7 x + 0.2 – (0.2) = 0.7 + (-0.2) x = 0.7 – 0.2 x = 0.5
x + 12 = -27 x + 12 - (12) = -27 + (-12) x = -27 + -12 = -39 x = -39
5x = 2.5 5x / (5) = 2.5 / (5) 2.5 / 5 = 0.5
2x + 8 = 20 2x + 8 – (8) = 20 – (8) 2x = 12 12 / 2 = 6
Without graphing the equation, we know the value of x = -3 because there are no other values for x with this problem, so we would plug in the value of x and solve for y. y = 4(-3) – 5 y = -12 -5 -12 + -5 = -17 x = -3, y = -17 (-3, -17)
-2y3(-6y3) -2 x -6 = 12 -y3 x -y3 = y6 Now combine. 12y |
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